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Check If Year Is Leap Year In Javascript Duplicate

Hey there, today we're diving into the world of JavaScript programming to understand how to check if a year is a leap year - a handy script to have at your disposal when working with date-related functionalities. So, let's break it down step by step!

A leap year is a year that contains an additional day in order to keep the calendar year synchronized with the astronomical year. In the Gregorian calendar, leap years occur in every year that is evenly divisible by 4, except for years that are both divisible by 100 and not divisible by 400.

To start checking if a year is a leap year in JavaScript, you can write a function that takes the year as an input parameter. Here's a simple function that accomplishes this:

Javascript

function isLeapYear(year) {
  return (year % 4 === 0 && year % 100 !== 0) || year % 400 === 0;
}

In this function:
- We use the modulo operator (%) to check if the year is divisible by 4 and not divisible by 100 or if it is divisible by 400.
- If the conditions are met, the function returns true, indicating that the year is a leap year. Otherwise, it returns false.

You can call this function with any year you want to check, like so:

Javascript

console.log(isLeapYear(2020)); // Output: true
console.log(isLeapYear(2021)); // Output: false

Feel free to integrate this function into your JavaScript projects where leap year calculations are needed. It's a concise and efficient way to determine leap years without much hassle.

Remember, writing clean and readable code is crucial when coding in any language, including JavaScript. By using simple and straightforward functions like the one above, you can make your code more maintainable and easier to understand for yourself and other developers who might work on it in the future.

And there you have it - a quick guide on how to check if a year is a leap year in JavaScript. Incorporate this function into your projects, and you'll never have to manually calculate leap years again. Happy coding!

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